The users of Local-Nursing-Homes.com have given Sienna Skilled Nursing & Rehabilitation an
average user rating of 5.0 out of 5 stars
based on 2 ratings.
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Sienna Skilled Nursing & Rehabilitation was given a 2 star overall rating
by The Centers for Medicare and Medicaid Services (CMS) [1],
placing it among the
lower 20–40%
of nursing homes in Ohio.
It also received
a 1 star rating for Health Inspections,
a 5 star rating for Quality Measures,
a 1 star rating for Nursing Staffing
and a 1 star rating for RN's Only.
Sienna Skilled Nursing & Rehabilitation has 88 beds
making this nursing home smaller than
the Ohio state average of 92.
The average number of beds per nursing home in
Jefferson County
is 66.
Additionally, the 82 residents at Sienna Skilled Nursing & Rehabilitation
are more than than
the average state nursing homes population of 75,
and is more full
at 93% than the 82% occupied average Ohio nursing home.
At the county level, Jefferson County
averages 54 residents per nursing home, for an average 80% occupation rate.
Sienna Skilled Nursing & Rehabilitation is located at 250 Cadiz Road
in Steubenville,
Ohio
43953.
The federal provider number for Sienna Skilled Nursing & Rehabilitation is 366331.
This nursing home accepts patients covered by
both
Medicare and Medicaid.
The owner of Sienna Skilled Nursing & Rehabilitation does not own any other nursing homes,
and is registered as a for profit - corporation
Find nursing jobs available at Sienna Skilled Nursing & Rehabilitation and other nearby facilities in Steubenville include openings for positions like
Certified Nursing Assistants (CNA),
Licensed Practical Nurses (LPN) and Licensed Vocational Nurses (LVN),
Registered Nurses (RN),
and other related positions in the fields of nursing home care and healthcare in general.